What is (9/8 \div 1/8)+8/8 ?

The solution to (9/8 \div 1/8)+8/8 is 10

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(9/8 \div 1/8)+8/8

(\frac{9}{8} \div \frac{1}{8}) + \frac{8}{8}

10

Solution steps

(\frac{9}{8} \div \frac{1}{8}) + \frac{8}{8}

\frac{8}{8} = 1

Apply rule

\frac{a}{a} = 1

1

= \frac{9}{8} \div \frac{1}{8} + 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{9}{8} \div \frac{1}{8} : 9

\frac{9}{8} \div \frac{1}{8}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{9}{8} \cdot \frac{8}{1}

Cross-cancel:

8

= \frac{9}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 9

= 9 + 1

Add and subtract (left to right)

9 + 1 : 10

9 + 1

9 + 1 = 10

= 10

= 10

(1 - 5)^{3}

(4 \times 2) + (6 \div 3) - 5

4 \times 13 - 3 \times 7 + 21 \div 3 + 9 - 13

6^{2} - 8 (6) + 5

(45 + 18 + 6^{2}) \div 3^{2} + (15 - 3) \div 5