What is (-4)^3+(-4)^2+10 ?

The solution to (-4)^3+(-4)^2+10 is -38

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(-4)^3+(-4)^2+10

(- 4)^{3} + (- 4)^{2} + 10

- 38

Solution steps

(- 4)^{3} + (- 4)^{2} + 10

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{3} : - 64

(- 4)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 4)^{3} = - 4^{3} = - 64

= - 64

= - 64 + (- 4)^{2} + 10

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 64 + 16 + 10

Add and subtract (left to right)

- 64 + 16 + 10 : - 38

- 64 + 16 + 10

- 64 + 16 = - 48

= - 48 + 10

- 48 + 10 = - 38

= - 38

= - 38

\frac{5}{9} (212 - 32)

(- 6)^{2} + 3 (- 6) - 6

- 2^{3} - 5

(78 + 5) + (38 + 4)

3^{2} + 2 (3) + 1