What is (-20)^2+8(-20) ?

The solution to (-20)^2+8(-20) is 240

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(-20)^2+8(-20)

(- 20)^{2} + 8 (- 20)

240

Solution steps

(- 20)^{2} + 8 (- 20)

Follow the PEMDAS order of operations

Calculate exponents

(- 20)^{2} : 400

(- 20)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 20)^{2} = 2 0^{2} = 400

= 400

= 400 + 8 (- 20)

Multiply and divide (left to right)

8 (- 20) : - 160

8 (- 20)

Apply rule

a \cdot (- b) = - a \cdot b

8 (- 20) = - 8 \cdot 20 = - 160

= - 160

= 400 - 160

Add and subtract (left to right)

400 - 160 : 240

400 - 160

400 - 160 = 240

= 240

= 240

2 (- 2)^{2} + 4

72 \div (7 - 1) \cdot 3

- 15 + 7 + 8 - 5 - 6 - 4 + 11 - 3

4 (3) + 5 (4)^{2} - 3 (2)

3 - 20 - 11 - 2 [- 18]