What is -3+1/3 (6+3) ?

The solution to -3+1/3 (6+3) is 0

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-3+1/3 (6+3)

- 3 + \frac{1}{3} (6 + 3)

0

Solution steps

- 3 + \frac{1}{3} (6 + 3)

Follow the PEMDAS order of operations

Calculate within parentheses

(6 + 3) : 9

6 + 3

6 + 3 = 9

= 9

= - 3 + \frac{1}{3} \cdot 9

Multiply and divide (left to right)

\frac{1}{3} \cdot 9 : 3

\frac{1}{3} \cdot 9

Convert element to fraction:

9 = \frac{9}{1}

= \frac{1}{3} \cdot \frac{9}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot 9}{3 \cdot 1}

\frac{1 \cdot 9}{3 \cdot 1} = 3

\frac{1 \cdot 9}{3 \cdot 1}

\frac{1 \cdot 9}{3 \cdot 1} = \frac{9}{3}

\frac{1 \cdot 9}{3 \cdot 1}

Multiply the numbers:

1 \cdot 9 = 9

= \frac{9}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{9}{3}

= \frac{9}{3}

Divide the numbers:

\frac{9}{3} = 3

= 3

= 3

= - 3 + 3

Add and subtract (left to right)

- 3 + 3 : 0

- 3 + 3

- 3 + 3 = 0

= 0

= 0

2 + (- 2) + 1 + (- 6)

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+ (- 7) - (- 13) + (- 4) + (+ 2)

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14 + [23 - (34 - 57)]