The solution to 1+1(-1/2) is 1/2

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1+1(-1/2)

Solution

1 + 1 (- \frac{1}{2})

\frac{1}{2}

Solution steps

1 + 1 \cdot (- \frac{1}{2})

Follow the PEMDAS order of operations

Multiply and divide (left to right)

1 \cdot (- \frac{1}{2}) : - \frac{1}{2}

1 \cdot (- \frac{1}{2})

Apply rule

a \cdot (- b) = - a \cdot b

1 \cdot (- \frac{1}{2}) = - 1 \cdot \frac{1}{2} = - \frac{1}{2}

= - \frac{1}{2}

= 1 - \frac{1}{2}

Add and subtract (left to right)

1 - \frac{1}{2} : \frac{1}{2}

1 - \frac{1}{2}

1 - \frac{1}{2} = \frac{1}{2}

1 - \frac{1}{2}

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= \frac{1 \cdot 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 2 - 1}{2}

1 \cdot 2 - 1 = 1

1 \cdot 2 - 1

Multiply the numbers:

1 \cdot 2 = 2

= 2 - 1

Subtract the numbers:

2 - 1 = 1

= 1

= \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2}

(- 3)^{2} + (- 1^{20}) + (- 2)^{0} - (- 3^{2})

(- 3)^{2} + (- 3)^{3}

6^{3} + 6^{4}

- 2 (- 4 + 3)^{2} - 1

18 - 2 \times 8