What is 1^2(1-5)(-4/250) ?

The solution to 1^2(1-5)(-4/250) is 8/125

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1^2(1-5)(-4/250)

1^{2} (1 - 5) (- \frac{4}{250})

\frac{8}{125}

Solution steps

1^{2} (1 - 5) (- \frac{4}{250})

\frac{4}{250} = \frac{2}{125}

Cancel the common factor:

2

\frac{2}{125}

= 1^{2} (1 - 5) (- \frac{2}{125})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - 5) : - 4

1 - 5

1 - 5 = - 4

= - 4

= 1^{2} (- 4) (- \frac{2}{125})

Calculate exponents

1^{2} : 1

1^{2}

1^{2} = 1

= 1

= 1 \cdot (- 4) (- \frac{2}{125})

Multiply and divide (left to right)

1 \cdot (- 4) (- \frac{2}{125}) : \frac{8}{125}

1 \cdot (- 4) (- \frac{2}{125})

Apply rule

a \cdot (- b) = - a \cdot b

1 \cdot (- 4) = - 1 \cdot 4 = - 4

= - 4 (- \frac{2}{125})

- 4 (- \frac{2}{125}) = \frac{8}{125}

- 4 (- \frac{2}{125})

Apply rule

- a \cdot (- b) = a \cdot b

- 4 (- \frac{2}{125}) = 4 \cdot \frac{2}{125}

Convert element to fraction:

4 = \frac{4}{1}

= \frac{4}{1} \cdot \frac{2}{125}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 2}{1 \cdot 125}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{8}{1 \cdot 125}

Multiply the numbers:

1 \cdot 125 = 125

= \frac{8}{125}

= \frac{8}{125}

= \frac{8}{125}

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