The solution to 10-96/5-3 is -61/5

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10-96/5-3

Solution

10 - \frac{96}{5} - 3

- \frac{61}{5}

Solution steps

10 - \frac{96}{5} - 3

Follow the PEMDAS order of operations

Add and subtract (left to right)

10 - \frac{96}{5} = - \frac{46}{5}

10 - \frac{96}{5}

Convert element to fraction:

10 = \frac{10 \cdot 5}{5}

= \frac{10 \cdot 5}{5} - \frac{96}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{10 \cdot 5 - 96}{5}

10 \cdot 5 - 96 = - 46

10 \cdot 5 - 96

Multiply the numbers:

10 \cdot 5 = 50

= 50 - 96

Subtract the numbers:

50 - 96 = - 46

= - 46

= \frac{- 46}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{46}{5}

= - \frac{46}{5} - 3

- \frac{46}{5} - 3 = - \frac{61}{5}

- \frac{46}{5} - 3

Convert element to fraction:

3 = \frac{3 \cdot 5}{5}

= - \frac{3 \cdot 5}{5} - \frac{46}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 3 \cdot 5 - 46}{5}

- 3 \cdot 5 - 46 = - 61

- 3 \cdot 5 - 46

Multiply the numbers:

3 \cdot 5 = 15

= - 15 - 46

Subtract the numbers:

- 15 - 46 = - 61

= - 61

= \frac{- 61}{5}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{61}{5}

= - \frac{61}{5}

7 (3) + \frac{6}{2} - 9

3 + 2 (\frac{8}{2})

2^{3} + 1 \cdot 6

(20 + 5) \times (25 - 10)

30 - (- 2) \cdot (- 10) + (- 5) \cdot (- 2)