What is 5/9 (-6\times 32) ?

The solution to 5/9 (-6\times 32) is -320/3

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5/9 (-6\times 32)

\frac{5}{9} (- 6 \cdot 32)

- \frac{320}{3}

Solution steps

\frac{5}{9} (- 6 \cdot 32)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 6 \cdot 32) : - 192

- 6 \cdot 32

- 6 \cdot 32 = - 192

= - 192

= \frac{5}{9} (- 192)

Multiply and divide (left to right)

\frac{5}{9} (- 192) : - \frac{320}{3}

\frac{5}{9} (- 192)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{5}{9} (- 192) = - \frac{5}{9} \cdot 192

Convert element to fraction:

192 = \frac{192}{1}

= - \frac{5}{9} \cdot \frac{192}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{5}{9} \cdot \frac{192}{1} = \frac{5 \cdot 192}{9 \cdot 1}

= - \frac{5 \cdot 192}{9 \cdot 1}

Cancel

\frac{5 \cdot 192}{9 \cdot 1} : \frac{320}{3}

\frac{5 \cdot 192}{9 \cdot 1}

Multiply the numbers:

9 \cdot 1 = 9

= \frac{5 \cdot 192}{9}

Factor the number:

192 = 3 \cdot 64

= \frac{5 \cdot 3 \cdot 64}{9}

Factor the number:

9 = 3 \cdot 3

= \frac{5 \cdot 3 \cdot 64}{3 \cdot 3}

Cancel the common factor:

3

= \frac{5 \cdot 64}{3}

Multiply the numbers:

5 \cdot 64 = 320

= \frac{320}{3}

= - \frac{320}{3}

= - \frac{320}{3}

8 \cdot 3 \div 4 \div (10 \div 2 - 4) + 20

0 - (- 72 \times 1)

6 \times (10 \times 5 + 8^{2}) - 6

2 (8) - 10

5 (2 \times (- 3)) - 7