What is -(-4)\div 12\div (-6) ?

The solution to -(-4)\div 12\div (-6) is -1/18

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-(-4)\div 12\div (-6)

- (- 4) \div 12 \div (- 6)

- \frac{1}{18}

Solution steps

- (- 4) \div 12 \div (- 6)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

Apply rule

- (- a) \div b = a \div b

- (- 4) \div 12 = 4 \div 12 = \frac{- ( - 4 )}{12}

= \frac{- ( - 4 )}{12} \div (- 6)

\frac{- ( - 4 )}{12} \div (- 6) = - \frac{1}{18}

\frac{- ( - 4 )}{12} \div (- 6)

Apply rule

a \div (- b) = - a \div b

\frac{- ( - 4 )}{12} \div (- 6) = - \frac{- ( - 4 )}{12} \div 6

Convert element to fraction:

6 = \frac{6}{1}

= - \frac{- ( - 4 )}{12} \div \frac{6}{1}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= - \frac{- ( - 4 )}{12} \cdot \frac{1}{6}

Apply rule

- (- a) = a

= - \frac{4}{12} \cdot \frac{1}{6}

Cross-cancel common factor:

2

4, 6

Greatest Common Divisor (GCD)

Prime factorization of

4 : 2 \cdot 2

4

4

divides by

24 = 2 \cdot 2

= 2 \cdot 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

The prime factors common to

4, 6

are

= 2

= \frac{2}{12} \cdot \frac{1}{3}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{2 \cdot 1}{12 \cdot 3}

Multiply the numbers:

2 \cdot 1 = 2

= - \frac{2}{12 \cdot 3}

Multiply the numbers:

12 \cdot 3 = 36

= - \frac{2}{36}

Cancel the common factor:

2

= - \frac{1}{18}

= - \frac{1}{18}

- 5 \times 8 + 10

(- 5 \times 6) + (- 8 \times 4)

+ 6 - 12 + 4 - 24

\frac{- 28 - 3 ( - 2 )}{2}

\frac{10}{3} (25)^{2}