What is (7/15+2/15)\div 5 ?

The solution to (7/15+2/15)\div 5 is 3/25

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(7/15+2/15)\div 5

(\frac{7}{15} + \frac{2}{15}) \div 5

\frac{3}{25}

Solution steps

(\frac{7}{15} + \frac{2}{15}) \div 5

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{7}{15} + \frac{2}{15}) : \frac{3}{5}

\frac{7}{15} + \frac{2}{15}

\frac{7}{15} + \frac{2}{15} = \frac{3}{5}

\frac{7}{15} + \frac{2}{15}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 + 2}{15}

Add the numbers:

7 + 2 = 9

= \frac{9}{15}

Cancel the common factor:

3

= \frac{3}{5}

= \frac{3}{5}

= \frac{3}{5} \div 5

Multiply and divide (left to right)

\frac{3}{5} \div 5 : \frac{3}{25}

\frac{3}{5} \div 5

Convert element to fraction:

5 = \frac{5}{1}

= \frac{3}{5} \div \frac{5}{1}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{3}{5} \cdot \frac{1}{5}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 1}{5 \cdot 5}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{3}{5 \cdot 5}

Multiply the numbers:

5 \cdot 5 = 25

= \frac{3}{25}

= \frac{3}{25}

2^{0} + 2^{3}

2^{0} + 2^{1}

(+ 3) + (- 8) + (+ 2) + (- 1)

6 (3) - 5

3^{3} - 4 \times 2 + 18 \div 3 + 2^{4} - 4^{2} + 11