What is 2+4/3-2 1/3 ?

The solution to 2+4/3-2 1/3 is 1

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2+4/3-2 1/3

2 + \frac{4}{3} - 2 \frac{1}{3}

1

Solution steps

2 + \frac{4}{3} - 2 \frac{1}{3}

Convert mixed numbers to improper fractions:

2 \frac{1}{3} = \frac{7}{3}

2 \frac{1}{3}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{1}{3} = \frac{2 \cdot 3 + 1}{3}

= \frac{7}{3}

= 2 + \frac{4}{3} - \frac{7}{3}

Follow the PEMDAS order of operations

Add and subtract (left to right)

2 + \frac{4}{3} - \frac{7}{3} : 1

2 + \frac{4}{3} - \frac{7}{3}

2 + \frac{4}{3} = \frac{10}{3}

2 + \frac{4}{3}

Convert element to fraction:

2 = \frac{2 \cdot 3}{3}

= \frac{2 \cdot 3}{3} + \frac{4}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 3 + 4}{3}

2 \cdot 3 + 4 = 10

2 \cdot 3 + 4

Multiply the numbers:

2 \cdot 3 = 6

= 6 + 4

Add the numbers:

6 + 4 = 10

= 10

= \frac{10}{3}

= \frac{10}{3} - \frac{7}{3}

\frac{10}{3} - \frac{7}{3} = 1

\frac{10}{3} - \frac{7}{3}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{10 - 7}{3}

Subtract the numbers:

10 - 7 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 1

= 1

- \frac{1}{4} (5)^{2} + 4

4 \cdot 5 - 6 \cdot (- 2)

\frac{1}{256} \div 2^{8}

2 - 4 (1)

2^{2} - 4 \cdot 2 \cdot 3