What is (-2-4)^2+(1)^2 ?

The solution to (-2-4)^2+(1)^2 is 37

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(-2-4)^2+(1)^2

(- 2 - 4)^{2} + (1)^{2}

37

Solution steps

(- 2 - 4)^{2} + (1)^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 - 4) : - 6

- 2 - 4

- 2 - 4 = - 6

= - 6

= (- 6)^{2} + (1)^{2}

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= 36 + (1)^{2}

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 36 + 1

Add and subtract (left to right)

36 + 1 : 37

36 + 1

36 + 1 = 37

= 37

= 37

4 - \frac{1}{2} - \frac{3}{9} - \frac{1}{4}

28 + (- 12) + 5

48 \times 6 \div 12

- 11 + 9 (- 7 + 3)

4 + 7 - 18 \div 3 - 2 \times 3 \times 4 - 42 \div 2 \div 7