What is (-1-4)/(-1-3) ?

The solution to (-1-4)/(-1-3) is 1 1/4

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(-1-4)/(-1-3)

\frac{- 1 - 4}{- 1 - 3}

1 \frac{1}{4}

Solution steps

\frac{- 1 - 4}{- 1 - 3}

Solve

- 1 - 4 : - 5

- 1 - 4 = - 5

= - 5

Solve

- 1 - 3 : - 4

Follow the PEMDAS order of operations

- 1 - 3 = - 4

= - 4

= \frac{- 5}{- 4}

Simplify

\frac{- 5}{- 4} : 1 \frac{1}{4}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5}{4}

Convert improper fractions to mixed numbers:

\frac{5}{4} = 1 \frac{1}{4}

\frac{5}{4} = 1

Remainder

1

\frac{5}{4}

Write the problem in long division format

4 \overline{∣ 5}

Divide

5

4

to get

1

Divide

5

4

to get

1

1 4 \overline{∣ 5}

Multiply the quotient digit

(1)

by the divisor

4

1 4 \overline{∣ 5} \underline{4}

Subtract

4

from

5

1 4 \overline{∣ 5} \underline{4} 1

1 4 \overline{∣ 5} \underline{4} 1

The solution for Long Division of

\frac{5}{4}

1

with remainder of

1

1 Remainder 1

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{5}{4} = 1 \frac{1}{4}

= 1 \frac{1}{4}

= 1 \frac{1}{4}

= 1 \frac{1}{4}

\frac{5 0 ^{2} - 8 0 ^{2}}{2}

16 (12)^{2}

9 - 2 [- 4 (4 - 8) - 3 (6 - 4)]

7 \div 12 + 2 \div 6

5^{2} + 5^{1} - 3^{2} + 2^{3}