What is 3(-3)^2+(5(-3)+10)^2+3(-3)-7 ?

The solution to 3(-3)^2+(5(-3)+10)^2+3(-3)-7 is 36

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3(-3)^2+(5(-3)+10)^2+3(-3)-7

3 (- 3)^{2} + (5 (- 3) + 10)^{2} + 3 (- 3) - 7

36

Solution steps

3 (- 3)^{2} + (5 (- 3) + 10)^{2} + 3 (- 3) - 7

Follow the PEMDAS order of operations

Calculate within parentheses

(5 (- 3) + 10) : - 5

5 (- 3) + 10

Multiply and divide (left to right)

5 (- 3) : - 15

5 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 3) = - 5 \cdot 3 = - 15

= - 15

= - 15 + 10

Add and subtract (left to right)

- 15 + 10 : - 5

- 15 + 10

- 15 + 10 = - 5

= - 5

= - 5

= 3 (- 3)^{2} + (- 5)^{2} + 3 (- 3) - 7

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 3 \cdot 9 + (- 5)^{2} + 3 (- 3) - 7

Calculate exponents

(- 5)^{2} : 25

(- 5)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{2} = 5^{2} = 25

= 25

= 3 \cdot 9 + 25 + 3 (- 3) - 7

Multiply and divide (left to right)

3 \cdot 9 : 27

3 \cdot 9

3 \cdot 9 = 27

= 27

= 27 + 25 + 3 (- 3) - 7

Multiply and divide (left to right)

3 (- 3) : - 9

3 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 3) = - 3 \cdot 3 = - 9

= - 9

= 27 + 25 - 9 - 7

Add and subtract (left to right)

27 + 25 - 9 - 7 : 36

27 + 25 - 9 - 7

27 + 25 = 52

= 52 - 9 - 7

52 - 9 = 43

= 43 - 7

43 - 7 = 36

= 36

= 36

(6)^{2} - 3

(- 3)^{3} - 27 (- 3)

4 ((- 4) - 11)^{2} + 4

(7 - 1 + 6)

- (- 4 + \frac{- 8}{3} + \frac{16}{4})

What is 3(-3)^2+(5(-3)+10)^2+3(-3)-7 ?
The solution to 3(-3)^2+(5(-3)+10)^2+3(-3)-7 is 36