What is (-2)/3 (10/2+(-2)+6) ?

The solution to (-2)/3 (10/2+(-2)+6) is -6

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(-2)/3 (10/2+(-2)+6)

\frac{- 2}{3} (\frac{10}{2} + (- 2) + 6)

- 6

Solution steps

\frac{- 2}{3} (\frac{10}{2} + (- 2) + 6)

Apply the fraction rule

\frac{- a}{b} = - \frac{a}{b}

- \frac{2}{3}

= (- \frac{2}{3}) (\frac{10}{2} - 2 + 6)

\frac{10}{2} = 5

Divide the numbers:

\frac{10}{2} = 5

5

= (- \frac{2}{3}) (5 - 2 + 6)

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 2 + 6) : 9

5 - 2 + 6

Add and subtract (left to right)

5 - 2 = 3

= 3 + 6

3 + 6 = 9

= 9

= (- \frac{2}{3}) \cdot 9

Multiply and divide (left to right)

(- \frac{2}{3}) \cdot 9 : - 6

(- \frac{2}{3}) \cdot 9

Apply rule

(- a) \cdot b = - a \cdot b

(- \frac{2}{3}) \cdot 9 = - \frac{2}{3} \cdot 9

Convert element to fraction:

9 = \frac{9}{1}

= - \frac{2}{3} \cdot \frac{9}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{2}{3} \cdot \frac{9}{1} = \frac{2 \cdot 9}{3 \cdot 1}

= - \frac{2 \cdot 9}{3 \cdot 1}

Cancel

\frac{2 \cdot 9}{3 \cdot 1} : 6

\frac{2 \cdot 9}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{2 \cdot 9}{3}

Divide the numbers:

\frac{9}{3} = 3

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

= - 6

= - 6

3 - 60 + 54 \times 4 + 6

3 (3) - 2 (- 1) + 4

8^{3} \cdot 2

(- 2)^{4} - 4 (- 2)^{2}

(4 \times 5) + 5