What is 5/7 \times 49-35 ?

The solution to 5/7 \times 49-35 is 0

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5/7 \times 49-35

\frac{5}{7} \cdot 49 - 35

0

Solution steps

\frac{5}{7} \cdot 49 - 35

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{5}{7} \cdot 49 : 35

\frac{5}{7} \cdot 49

Convert element to fraction:

49 = \frac{49}{1}

= \frac{5}{7} \cdot \frac{49}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{5 \cdot 49}{7 \cdot 1}

Cancel

\frac{5 \cdot 49}{7 \cdot 1} : 35

\frac{5 \cdot 49}{7 \cdot 1}

Multiply the numbers:

7 \cdot 1 = 7

= \frac{5 \cdot 49}{7}

Divide the numbers:

\frac{49}{7} = 7

= 5 \cdot 7

Multiply the numbers:

5 \cdot 7 = 35

= 35

= 35

= 35 - 35

Add and subtract (left to right)

35 - 35 : 0

35 - 35

35 - 35 = 0

= 0

= 0

(- 5)^{0} + 8^{1} + (- 3)^{3}

[(66 \div 11)^{2} - 6] \cdot 5 + 5

- (- 1 - 3)^{2} - 2

- 9 - (- 8) - 15 - 17 - (- 32) + 0

- 32 (5) + 256