What is 4(4/5)+4(1/5)+(-4) ?

The solution to 4(4/5)+4(1/5)+(-4) is 0

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4(4/5)+4(1/5)+(-4)

4 (\frac{4}{5}) + 4 (\frac{1}{5}) + (- 4)

0

Solution steps

4 (\frac{4}{5}) + 4 (\frac{1}{5}) + (- 4)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

4 (\frac{4}{5}) : \frac{16}{5}

4 (\frac{4}{5})

Apply rule:

(a) = a

(\frac{4}{5}) = \frac{4}{5}

= 4 \cdot \frac{4}{5}

4 \cdot \frac{4}{5} = \frac{16}{5}

4 \cdot \frac{4}{5}

Convert element to fraction:

4 = \frac{4}{1}

= \frac{4}{1} \cdot \frac{4}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 4}{1 \cdot 5}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{16}{1 \cdot 5}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{16}{5}

= \frac{16}{5}

= \frac{16}{5} + 4 (\frac{1}{5}) + (- 4)

Multiply and divide (left to right)

4 (\frac{1}{5}) : \frac{4}{5}

4 (\frac{1}{5})

Apply rule:

(a) = a

(\frac{1}{5}) = \frac{1}{5}

= 4 \cdot \frac{1}{5}

4 \cdot \frac{1}{5} = \frac{4}{5}

4 \cdot \frac{1}{5}

Convert element to fraction:

4 = \frac{4}{1}

= \frac{4}{1} \cdot \frac{1}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 1}{1 \cdot 5}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{4}{1 \cdot 5}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{4}{5}

= \frac{4}{5}

= \frac{16}{5} + \frac{4}{5} + (- 4)

Add and subtract (left to right)

\frac{16}{5} + \frac{4}{5} + (- 4) : 0

\frac{16}{5} + \frac{4}{5} + (- 4)

\frac{16}{5} + \frac{4}{5} = 4

\frac{16}{5} + \frac{4}{5}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{16 + 4}{5}

Add the numbers:

16 + 4 = 20

= \frac{20}{5}

Divide the numbers:

\frac{20}{5} = 4

= 4

= 4 + (- 4)

Apply rule

+ (- a) = - a

+ (- 4) = - 4

= 4 - 4

4 - 4 = 0

= 0

= 0

\frac{7 ^{4} + 21 \times 7 ^{2}}{7 ^{3}}

4 (1) + 6

(1^{2} + 1)^{2}

1 + \frac{1}{4}

1 + \frac{1}{2}