What is 6\times 1/5+1/3 ?

The solution to 6\times 1/5+1/3 is 1 8/15

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Popular >

6\times 1/5+1/3

Solution

6 \cdot \frac{1}{5} + \frac{1}{3}

Solution

1 \frac{8}{15}

Solution steps

6 \cdot \frac{1}{5} + \frac{1}{3}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

6 \cdot \frac{1}{5} : \frac{6}{5}

6 \cdot \frac{1}{5}

Convert element to fraction:

6 = \frac{6}{1}

= \frac{6}{1} \cdot \frac{1}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{6 \cdot 1}{1 \cdot 5}

Multiply the numbers:

6 \cdot 1 = 6

= \frac{6}{1 \cdot 5}

Multiply the numbers:

1 \cdot 5 = 5

= \frac{6}{5}

= \frac{6}{5} + \frac{1}{3}

Add and subtract (left to right)

\frac{6}{5} + \frac{1}{3} : \frac{23}{15}

\frac{6}{5} + \frac{1}{3}

\frac{6}{5} + \frac{1}{3} = \frac{23}{15}

\frac{6}{5} + \frac{1}{3}

Least Common Multiplier of

5, 3 : 15

5, 3

Least Common Multiplier (LCM)

Prime factorization of

5 : 5

5

5

is a prime number, therefore no factorization is possible

= 5

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Multiply each factor the greatest number of times it occurs in either

5

3

= 5 \cdot 3

Multiply the numbers:

5 \cdot 3 = 15

= 15

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

15

For

\frac{6}{5} :

multiply the denominator and numerator by

3

\frac{6}{5} = \frac{6 \cdot 3}{5 \cdot 3} = \frac{18}{15}

For

\frac{1}{3} :

multiply the denominator and numerator by

5

\frac{1}{3} = \frac{1 \cdot 5}{3 \cdot 5} = \frac{5}{15}

= \frac{18}{15} + \frac{5}{15}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{18 + 5}{15}

Add the numbers:

18 + 5 = 23

= \frac{23}{15}

= \frac{23}{15}

= \frac{23}{15}

Convert improper fractions to mixed numbers:

\frac{23}{15} = 1 \frac{8}{15}

\frac{23}{15} = 1

Remainder

8

\frac{23}{15}

Write the problem in long division format

15 \overline{∣ 23}

Divide

23

15

to get

1

Divide

23

15

to get

1

1 15 \overline{∣ 23}

Multiply the quotient digit

(1)

by the divisor

15

1 15 \overline{∣ 23} \underline{15}

Subtract

15

from

23

1 15 \overline{∣ 23} \underline{15} 8

1 15 \overline{∣ 23} \underline{15} 8

The solution for Long Division of

\frac{23}{15}

1

with remainder of

8

1 Remainder 8

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{23}{15} = 1 \frac{8}{15}

= 1 \frac{8}{15}

= 1 \frac{8}{15}

Popular Examples

-452+365-156

- 452 + 365 - 156

40\div 2^3+2

40 \div 2^{3} + 2

(-72)*(-2)\div (-4)*(3)

(- 72) \cdot (- 2) \div (- 4) \cdot (3)

6-(-9+7-1)-(3-(-5+4+6)-1)

6 - (- 9 + 7 - 1) - (3 - (- 5 + 4 + 6) - 1)

(32\div (-7+5))(-7)-(-13)

(32 \div (- 7 + 5)) (- 7) - (- 13)

Frequently Asked Questions (FAQ)

What is 6\times 1/5+1/3 ?
The solution to 6\times 1/5+1/3 is 1 8/15