What is 1/2 (-8+(-12))+14 ?

The solution to 1/2 (-8+(-12))+14 is 4

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1/2 (-8+(-12))+14

\frac{1}{2} (- 8 + (- 12)) + 14

4

Solution steps

\frac{1}{2} (- 8 + (- 12)) + 14

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8 + (- 12)) : - 20

- 8 + (- 12)

Add and subtract (left to right)

Apply rule

+ (- a) = - a

+ (- 12) = - 12

= - 8 - 12

- 8 - 12 = - 20

= - 20

= \frac{1}{2} (- 20) + 14

Multiply and divide (left to right)

\frac{1}{2} (- 20) : - 10

\frac{1}{2} (- 20)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{2} (- 20) = - \frac{1}{2} \cdot 20

Convert element to fraction:

20 = \frac{20}{1}

= - \frac{1}{2} \cdot \frac{20}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{1}{2} \cdot \frac{20}{1} = \frac{1 \cdot 20}{2 \cdot 1}

= - \frac{1 \cdot 20}{2 \cdot 1}

\frac{1 \cdot 20}{2 \cdot 1} = 10

\frac{1 \cdot 20}{2 \cdot 1}

\frac{1 \cdot 20}{2 \cdot 1} = \frac{20}{2}

\frac{1 \cdot 20}{2 \cdot 1}

Multiply the numbers:

1 \cdot 20 = 20

= \frac{20}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{20}{2}

= \frac{20}{2}

Divide the numbers:

\frac{20}{2} = 10

= 10

= - 10

= - 10 + 14

Add and subtract (left to right)

- 10 + 14 : 4

- 10 + 14

- 10 + 14 = 4

= 4

= 4

- 2 + 3 \cdot (- 17 - 2) - 29

(- 2)^{2} - (- 4)^{2} + 8 (- 3) - 25

- 8 - 30 (- 12) - 7

12 - [7 - (2 - 10)]

- 3 + 5 - 2 + 3 + 7