What is 1/2 \times 1-1 ?

The solution to 1/2 \times 1-1 is -1/2

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1/2 \times 1-1

\frac{1}{2} \cdot 1 - 1

- \frac{1}{2}

Solution steps

\frac{1}{2} \cdot 1 - 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{1}{2} \cdot 1 : \frac{1}{2}

\frac{1}{2} \cdot 1

\frac{1}{2} \cdot 1 = \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2} - 1

Add and subtract (left to right)

\frac{1}{2} - 1 : - \frac{1}{2}

\frac{1}{2} - 1

\frac{1}{2} - 1 = - \frac{1}{2}

\frac{1}{2} - 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 + 1}{2}

- 1 \cdot 2 + 1 = - 1

- 1 \cdot 2 + 1

Multiply the numbers:

1 \cdot 2 = 2

= - 2 + 1

Add/Subtract the numbers:

- 2 + 1 = - 1

= - 1

= \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

= - \frac{1}{2}

= - \frac{1}{2}

- 14 \times (- 15) \div (- 21)

6 (1) - 3 (1)^{2}

1 6^{2} - 1 0^{2}

- 6 (10 - 9) + 7 (3 - 5) \times 2

12 \times (- 4) + 7^{2}