What is (-2-10)^2+(4-2(-6)^2) ?

The solution to (-2-10)^2+(4-2(-6)^2) is 76

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(-2-10)^2+(4-2(-6)^2)

(- 2 - 10)^{2} + (4 - 2 (- 6)^{2})

76

Solution steps

(- 2 - 10)^{2} + (4 - 2 (- 6)^{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 - 10) : - 12

- 2 - 10

- 2 - 10 = - 12

= - 12

= (- 12)^{2} + (4 - 2 (- 6)^{2})

Calculate within parentheses

(4 - 2 (- 6)^{2}) : - 68

4 - 2 (- 6)^{2}

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= 4 - 2 \cdot 36

Multiply and divide (left to right)

2 \cdot 36 : 72

2 \cdot 36

2 \cdot 36 = 72

= 72

= 4 - 72

Add and subtract (left to right)

4 - 72 : - 68

4 - 72

4 - 72 = - 68

= - 68

= - 68

= (- 12)^{2} - 68

Calculate exponents

(- 12)^{2} : 144

(- 12)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 12)^{2} = 1 2^{2} = 144

= 144

= 144 - 68

Add and subtract (left to right)

144 - 68 : 76

144 - 68

144 - 68 = 76

= 76

= 76

14 \times + 17 + 16

2 [(- 9) (2^{3}) + (7) (4)]

(- 4 + 8)^{2}

- 2 \times 2^{2} + 3 \times 2 - 1

(- 3 - 2) - (- 6 + 2)