What is 54+4+6+3(26)+4(20) ?

The solution to 54+4+6+3(26)+4(20) is 222

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54+4+6+3(26)+4(20)

54 + 4 + 6 + 3 (26) + 4 (20)

222

Solution steps

54 + 4 + 6 + 3 (26) + 4 (20)

Follow the PEMDAS order of operations

Multiply and divide (left to right)

3 (26) : 78

3 (26)

Apply rule:

(a) = a

(26) = 26

= 3 \cdot 26

Multiply the numbers:

3 \cdot 26 = 78

= 78

= 54 + 4 + 6 + 78 + 4 (20)

Multiply and divide (left to right)

4 (20) : 80

4 (20)

Apply rule:

(a) = a

(20) = 20

= 4 \cdot 20

Multiply the numbers:

4 \cdot 20 = 80

= 80

= 54 + 4 + 6 + 78 + 80

Add and subtract (left to right)

54 + 4 + 6 + 78 + 80 : 222

54 + 4 + 6 + 78 + 80

54 + 4 = 58

= 58 + 6 + 78 + 80

58 + 6 = 64

= 64 + 78 + 80

64 + 78 = 142

= 142 + 80

142 + 80 = 222

= 222

= 222

- \frac{2}{5} (0) - 2

- (1 - 1)^{2} + 2

(\times (- 6)) (\times (- 1))

3 \times 2^{4} - 2 \div 2 + 9

0 \div 5 + 9 \div 3