What is -4(-2)^2+2(-2) ?

The solution to -4(-2)^2+2(-2) is -20

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-4(-2)^2+2(-2)

- 4 (- 2)^{2} + 2 (- 2)

- 20

Solution steps

- 4 (- 2)^{2} + 2 (- 2)

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 4 \cdot 4 + 2 (- 2)

Multiply and divide (left to right)

- 4 \cdot 4 : - 16

- 4 \cdot 4

- 4 \cdot 4 = - 16

= - 16

= - 16 + 2 (- 2)

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= - 16 - 4

Add and subtract (left to right)

- 16 - 4 : - 20

- 16 - 4

- 16 - 4 = - 20

= - 20

= - 20

- (- 1 - \frac{3}{4})

\frac{6}{3} - \frac{5}{7}

4^{4} - 0^{10}

18 \times 6 - 12

- 2 (4)^{2} + 12 (4) - 15