What is (1\div 2)+(1\div 2) ?

The solution to (1\div 2)+(1\div 2) is 1

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(1\div 2)+(1\div 2)

(1 \div 2) + (1 \div 2)

1

Solution steps

(1 \div 2) + (1 \div 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(1 \div 2) : \frac{1}{2}

1 \div 2

1 \div 2 = \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2} + (1 \div 2)

Calculate within parentheses

(1 \div 2) : \frac{1}{2}

1 \div 2

1 \div 2 = \frac{1}{2}

= \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Add and subtract (left to right)

\frac{1}{2} + \frac{1}{2} : 1

\frac{1}{2} + \frac{1}{2}

\frac{1}{2} + \frac{1}{2} = 1

\frac{1}{2} + \frac{1}{2}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 + 1}{2}

Add the numbers:

1 + 1 = 2

= \frac{2}{2}

Apply rule

\frac{a}{a} = 1

= 1

= 1

= 1

7 + 3 (1 + 5 (2 (9 - 7) + 4) + 2)

\frac{2 ( - 2 ) - 3}{4}

\frac{1}{3} + \frac{1}{5}

3^{2} - 3 - 1

7^{2} \times 4