What is -(4)^2+8(4)-12 ?

The solution to -(4)^2+8(4)-12 is 4

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-(4)^2+8(4)-12

- (4)^{2} + 8 (4) - 12

4

Solution steps

- (4)^{2} + 8 (4) - 12

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= - 16 + 8 (4) - 12

Multiply and divide (left to right)

8 (4) : 32

8 (4)

Apply rule:

(a) = a

(4) = 4

= 8 \cdot 4

Multiply the numbers:

8 \cdot 4 = 32

= 32

= - 16 + 32 - 12

Add and subtract (left to right)

- 16 + 32 - 12 : 4

- 16 + 32 - 12

- 16 + 32 = 16

= 16 - 12

16 - 12 = 4

= 4

= 4

(- 1) (- 9) (- 1)^{12}

1 0^{2} \div 25 + 4 \times 7^{2} \div 1 4^{1} - 12 + 2

- 3^{2} + 6 (- 3)

3 - 7 \times 2 - 5 \times 9 + 4 \times 6 \div 2 - 3

- 2 (- 3)^{2} - 5 (- 3) + 7