What is (-1)^3-4(-1)^2+5(-1)+2 ?

The solution to (-1)^3-4(-1)^2+5(-1)+2 is -8

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(-1)^3-4(-1)^2+5(-1)+2

(- 1)^{3} - 4 (- 1)^{2} + 5 (- 1) + 2

- 8

Solution steps

(- 1)^{3} - 4 (- 1)^{2} + 5 (- 1) + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 1 - 4 (- 1)^{2} + 5 (- 1) + 2

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 - 4 \cdot 1 + 5 (- 1) + 2

Multiply and divide (left to right)

4 \cdot 1 : 4

4 \cdot 1

4 \cdot 1 = 4

= 4

= - 1 - 4 + 5 (- 1) + 2

Multiply and divide (left to right)

5 (- 1) : - 5

5 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 1) = - 5 \cdot 1 = - 5

= - 5

= - 1 - 4 - 5 + 2

Add and subtract (left to right)

- 1 - 4 - 5 + 2 : - 8

- 1 - 4 - 5 + 2

- 1 - 4 = - 5

= - 5 - 5 + 2

- 5 - 5 = - 10

= - 10 + 2

- 10 + 2 = - 8

= - 8

= - 8

2 \cdot 0 - 5

(- 5) + (- 5) \cdot 4 - (- 2) \cdot (- 9)

7^{4} - 3^{2}

8^{2} - 4 (8) (2)

5 \times 7 + 2 \times 7^{2}