What is (-1)^3-2(-1)^2+3(-1)+5 ?

The solution to (-1)^3-2(-1)^2+3(-1)+5 is -1

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(-1)^3-2(-1)^2+3(-1)+5

(- 1)^{3} - 2 (- 1)^{2} + 3 (- 1) + 5

- 1

Solution steps

(- 1)^{3} - 2 (- 1)^{2} + 3 (- 1) + 5

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 1 - 2 (- 1)^{2} + 3 (- 1) + 5

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= - 1 - 2 \cdot 1 + 3 (- 1) + 5

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= - 1 - 2 + 3 (- 1) + 5

Multiply and divide (left to right)

3 (- 1) : - 3

3 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 1) = - 3 \cdot 1 = - 3

= - 3

= - 1 - 2 - 3 + 5

Add and subtract (left to right)

- 1 - 2 - 3 + 5 : - 1

- 1 - 2 - 3 + 5

- 1 - 2 = - 3

= - 3 - 3 + 5

- 3 - 3 = - 6

= - 6 + 5

- 6 + 5 = - 1

= - 1

= - 1

5 - 2 (6 - 10) \div 4

- 3 (- 2)^{2} - 6 (- 2) + 9

2 (1)^{2} - 1 + 2

- [(8 + 3) - (5 - 1)] + [(8 - 3) - (5 - 1)]

(- 2)^{3} + 3 (- 2)^{2} + 2 (- 2) - 5