What is (5^2+5)(5^3-3^5) ?

The solution to (5^2+5)(5^3-3^5) is -3540

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(5^2+5)(5^3-3^5)

(5^{2} + 5) (5^{3} - 3^{5})

- 3540

Solution steps

(5^{2} + 5) (5^{3} - 3^{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(5^{2} + 5) : 30

5^{2} + 5

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= 25 + 5

Add and subtract (left to right)

25 + 5 : 30

25 + 5

25 + 5 = 30

= 30

= 30

= 30 (5^{3} - 3^{5})

Calculate within parentheses

(5^{3} - 3^{5}) : - 118

5^{3} - 3^{5}

Calculate exponents

5^{3} : 125

5^{3}

5^{3} = 125

= 125

= 125 - 3^{5}

Calculate exponents

3^{5} : 243

3^{5}

3^{5} = 243

= 243

= 125 - 243

Add and subtract (left to right)

125 - 243 : - 118

125 - 243

125 - 243 = - 118

= - 118

= - 118

= 30 (- 118)

Multiply and divide (left to right)

30 (- 118) : - 3540

30 (- 118)

Apply rule

a \cdot (- b) = - a \cdot b

30 (- 118) = - 30 \cdot 118 = - 3540

= - 3540

= - 3540

- 2 (- 3) - 5

[(2 + 5 + 2 + 5^{2}) + 2^{3}] \div 6

4^{2} - 4 \times 4

- 5 (- 2)^{2} - 20 (- 2) - 26

(\frac{13}{5} - \frac{1}{2}) + \frac{1}{6}