What is 5*5-(1-(-2)^2)^2 ?

The solution to 5*5-(1-(-2)^2)^2 is 16

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5*5-(1-(-2)^2)^2

5 \cdot 5 - (1 - (- 2)^{2})^{2}

16

Solution steps

5 \cdot 5 - (1 - (- 2)^{2})^{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - (- 2)^{2}) : - 3

1 - (- 2)^{2}

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 1 - 4

Add and subtract (left to right)

1 - 4 : - 3

1 - 4

1 - 4 = - 3

= - 3

= - 3

= 5 \cdot 5 - (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 5 \cdot 5 - 9

Multiply and divide (left to right)

5 \cdot 5 : 25

5 \cdot 5

5 \cdot 5 = 25

= 25

= 25 - 9

Add and subtract (left to right)

25 - 9 : 16

25 - 9

25 - 9 = 16

= 16

= 16

(5 - 3^{2})^{3}

\frac{6}{2 \cdot ( 2 + 1 )}

8 (2) + 5

\frac{3}{4} (- 1)^{2} - 2 (- 1) + 1

(- 8 \times (- 6)) - 4^{2}