What is -2^3+6(-2)^2+13(-2)+10 ?

The solution to -2^3+6(-2)^2+13(-2)+10 is 0

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-2^3+6(-2)^2+13(-2)+10

- 2^{3} + 6 (- 2)^{2} + 13 (- 2) + 10

0

Solution steps

- 2^{3} + 6 (- 2)^{2} + 13 (- 2) + 10

Follow the PEMDAS order of operations

Calculate exponents

2^{3} : 8

2^{3}

2^{3} = 8

= 8

= - 8 + 6 (- 2)^{2} + 13 (- 2) + 10

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 8 + 6 \cdot 4 + 13 (- 2) + 10

Multiply and divide (left to right)

6 \cdot 4 : 24

6 \cdot 4

6 \cdot 4 = 24

= 24

= - 8 + 24 + 13 (- 2) + 10

Multiply and divide (left to right)

13 (- 2) : - 26

13 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

13 (- 2) = - 13 \cdot 2 = - 26

= - 26

= - 8 + 24 - 26 + 10

Add and subtract (left to right)

- 8 + 24 - 26 + 10 : 0

- 8 + 24 - 26 + 10

- 8 + 24 = 16

= 16 - 26 + 10

16 - 26 = - 10

= - 10 + 10

- 10 + 10 = 0

= 0

= 0

1^{0} - 1^{100}

(150 - 60 \div 3) - 9 \times 6 - (24 \div 3 \times 4)

1 5^{2} \div 3^{2}

(3)^{2} - 3 (3) \times (3 (3) - 2)

- 18 (+ 12 - 15 + 22) - (14 + 15 - 35)