What is -(1)^2-6(1)+7 ?

The solution to -(1)^2-6(1)+7 is 0

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-(1)^2-6(1)+7

- (1)^{2} - 6 (1) + 7

0

Solution steps

- (1)^{2} - 6 (1) + 7

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= - 1 - 6 (1) + 7

Multiply and divide (left to right)

6 (1) : 6

6 (1)

Apply rule:

(a) = a

(1) = 1

= 6 \cdot 1

Multiply the numbers:

6 \cdot 1 = 6

= 6

= - 1 - 6 + 7

Add and subtract (left to right)

- 1 - 6 + 7 : 0

- 1 - 6 + 7

- 1 - 6 = - 7

= - 7 + 7

- 7 + 7 = 0

= 0

= 0

3 - 5 + 12

6 (5)^{2} - 15

3 - 2 (- 3)

- \frac{1}{2} (1) + \frac{1}{2}

99 - 59 + 40 \div 4 \times 7