What is (+7)-(-8+2)^2-3*(-2)^3 ?

The solution to (+7)-(-8+2)^2-3*(-2)^3 is -5

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(+7)-(-8+2)^2-3*(-2)^3

(+ 7) - (- 8 + 2)^{2} - 3 \cdot (- 2)^{3}

- 5

Solution steps

(7) - (- 8 + 2)^{2} - 3 (- 2)^{3}

Follow the PEMDAS order of operations

Calculate within parentheses

(- 8 + 2) : - 6

- 8 + 2

- 8 + 2 = - 6

= - 6

= (7) - (- 6)^{2} - 3 (- 2)^{3}

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= (7) - 36 - 3 (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= (7) - 36 - 3 (- 8)

Multiply and divide (left to right)

3 (- 8) : - 24

3 (- 8)

Apply rule

a \cdot (- b) = - a \cdot b

3 (- 8) = - 3 \cdot 8 = - 24

= - 24

= (7) - 36 - (- 24)

Add and subtract (left to right)

(7) - 36 - (- 24) : - 5

(7) - 36 - (- 24)

(7) - 36 = - 29

= - 29 - (- 24)

Apply rule

- (- a) = + a

- (- 24) = + 24

= - 29 + 24

- 29 + 24 = - 5

= - 5

= - 5

4 (30) - 6

(- 1)^{5} - 2^{6}

8 - 3 + 2

\frac{[ ( - \frac{3}{5} - \frac{2}{5} + \frac{1}{5} ) + ( - \frac{1}{5} ) ]}{( - 7/2 )}

(4 \times 8 - 3 + 5) \times 4 + 2