What is (-8)^2+7(-8)-8 ?

The solution to (-8)^2+7(-8)-8 is 0

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(-8)^2+7(-8)-8

(- 8)^{2} + 7 (- 8) - 8

0

Solution steps

(- 8)^{2} + 7 (- 8) - 8

Follow the PEMDAS order of operations

Calculate exponents

(- 8)^{2} : 64

(- 8)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 8)^{2} = 8^{2} = 64

= 64

= 64 + 7 (- 8) - 8

Multiply and divide (left to right)

7 (- 8) : - 56

7 (- 8)

Apply rule

a \cdot (- b) = - a \cdot b

7 (- 8) = - 7 \cdot 8 = - 56

= - 56

= 64 - 56 - 8

Add and subtract (left to right)

64 - 56 - 8 : 0

64 - 56 - 8

64 - 56 = 8

= 8 - 8

8 - 8 = 0

= 0

= 0

9^{2} - 13

9^{2} - 12

2 (5 + 6)

(5 - 3) (5 - 3)

- 12 + 16 + (- 18)