What is (1-2/5)\div (2-1/2) ?

The solution to (1-2/5)\div (2-1/2) is 2/5

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(1-2/5)\div (2-1/2)

(1 - \frac{2}{5}) \div (2 - \frac{1}{2})

\frac{2}{5}

Solution steps

(1 - \frac{2}{5}) \div (2 - \frac{1}{2})

Follow the PEMDAS order of operations

Calculate within parentheses

(1 - \frac{2}{5}) : \frac{3}{5}

1 - \frac{2}{5}

1 - \frac{2}{5} = \frac{3}{5}

1 - \frac{2}{5}

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{2}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 2}{5}

1 \cdot 5 - 2 = 3

1 \cdot 5 - 2

Multiply the numbers:

1 \cdot 5 = 5

= 5 - 2

Subtract the numbers:

5 - 2 = 3

= 3

= \frac{3}{5}

= \frac{3}{5}

= \frac{3}{5} \div (2 - \frac{1}{2})

Calculate within parentheses

(2 - \frac{1}{2}) : \frac{3}{2}

2 - \frac{1}{2}

2 - \frac{1}{2} = \frac{3}{2}

2 - \frac{1}{2}

Convert element to fraction:

2 = \frac{2 \cdot 2}{2}

= \frac{2 \cdot 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 2 - 1}{2}

2 \cdot 2 - 1 = 3

2 \cdot 2 - 1

Multiply the numbers:

2 \cdot 2 = 4

= 4 - 1

Subtract the numbers:

4 - 1 = 3

= 3

= \frac{3}{2}

= \frac{3}{2}

= \frac{3}{5} \div \frac{3}{2}

Multiply and divide (left to right)

\frac{3}{5} \div \frac{3}{2} : \frac{2}{5}

\frac{3}{5} \div \frac{3}{2}

Apply the fraction rule:

\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

= \frac{3}{5} \cdot \frac{2}{3}

Cross-cancel:

3

= \frac{2}{5}

= \frac{2}{5}

\frac{( - 3 ) ^{3}}{( - 3 ) ^{2}}

3 (1 - 1) + 3

\frac{3}{4} - \frac{4}{12}

3 + [4 - 3 (9 - 2) + 21]

0 - (1 \times (- \frac{1}{2}))