What is (-2)^3+(-4)^2-5^2+(-1)^5 ?

The solution to (-2)^3+(-4)^2-5^2+(-1)^5 is -18

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(-2)^3+(-4)^2-5^2+(-1)^5

(- 2)^{3} + (- 4)^{2} - 5^{2} + (- 1)^{5}

- 18

Solution steps

(- 2)^{3} + (- 4)^{2} - 5^{2} + (- 1)^{5}

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= - 8 + (- 4)^{2} - 5^{2} + (- 1)^{5}

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - 8 + 16 - 5^{2} + (- 1)^{5}

Calculate exponents

5^{2} : 25

5^{2}

5^{2} = 25

= 25

= - 8 + 16 - 25 + (- 1)^{5}

Calculate exponents

(- 1)^{5} : - 1

(- 1)^{5}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{5} = - 1^{5} = - 1

= - 1

= - 8 + 16 - 25 - 1

Add and subtract (left to right)

- 8 + 16 - 25 - 1 : - 18

- 8 + 16 - 25 - 1

- 8 + 16 = 8

= 8 - 25 - 1

8 - 25 = - 17

= - 17 - 1

- 17 - 1 = - 18

= - 18

= - 18

- (- 4) + 10 + (- 12) - 8 + 12

196 - 52 + 23 - 14 - 29 - 18 - 32

- 7 + (- 2) + (- 8)

[4 - (5 - 4) + (- 5)]

(3^{4} \times 3^{2}) \div 3^{9}

What is (-2)^3+(-4)^2-5^2+(-1)^5 ?
The solution to (-2)^3+(-4)^2-5^2+(-1)^5 is -18