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Popular >

3^0-2^0+(-2)^0

Solution

3^{0} - 2^{0} + (- 2)^{0}

Solution

1

Solution steps

3^{0} - 2^{0} + (- 2)^{0}

Follow the PEMDAS order of operations

Calculate exponents

3^{0} : 1

3^{0}

3^{0} = 1

= 1

= 1 - 2^{0} + (- 2)^{0}

Calculate exponents

2^{0} : 1

2^{0}

2^{0} = 1

= 1

= 1 - 1 + (- 2)^{0}

Calculate exponents

(- 2)^{0} : 1

(- 2)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

if

n

is even

(- 2)^{0} = 2^{0} = 1

= 1

= 1 - 1 + 1

Add and subtract (left to right)

1 - 1 + 1 : 1

1 - 1 + 1

1 - 1 = 0

= 0 + 1

0 + 1 = 1

= 1

= 1

Popular Examples

\frac{1}{3} \times 1 + 3

(5 + 1) (5 - 1)

2^3-2^2+24\div 12*3

2^{3} - 2^{2} + 24 \div 12 \cdot 3

(8 - 2) [5 - (1 + 3)]

8+8+8+3-12-2\times 6+6

8 + 8 + 8 + 3 - 12 - 2 \times 6 + 6

Frequently Asked Questions (FAQ)

What is 3^0-2^0+(-2)^0 ?
The solution to 3^0-2^0+(-2)^0 is 1