What is 3(-1)^2-4(-1)+4 ?

The solution to 3(-1)^2-4(-1)+4 is 11

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3(-1)^2-4(-1)+4

3 (- 1)^{2} - 4 (- 1) + 4

11

Solution steps

3 (- 1)^{2} - 4 (- 1) + 4

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 3 \cdot 1 - 4 (- 1) + 4

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 - 4 (- 1) + 4

Multiply and divide (left to right)

4 (- 1) : - 4

4 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 1) = - 4 \cdot 1 = - 4

= - 4

= 3 - (- 4) + 4

Add and subtract (left to right)

3 - (- 4) + 4 : 11

3 - (- 4) + 4

Apply rule

- (- a) = + a

- (- 4) = + 4

= 3 + 4 + 4

3 + 4 = 7

= 7 + 4

7 + 4 = 11

= 11

= 11

35 \cdot 35

2 (7 - 4) + 3 (1 - 5) + 8

11 \cdot 12

- 65 + \frac{6}{( - 3 )} + 40

4^{2} \cdot 2 - 30 \cdot \frac{2}{6} + 4 \cdot 3