What is 3^3+2(3)^2-8(3)-21 ?

The solution to 3^3+2(3)^2-8(3)-21 is 0

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3^3+2(3)^2-8(3)-21

3^{3} + 2 (3)^{2} - 8 (3) - 21

0

Solution steps

3^{3} + 2 (3)^{2} - 8 (3) - 21

Follow the PEMDAS order of operations

Calculate exponents

3^{3} : 27

3^{3}

3^{3} = 27

= 27

= 27 + 2 (3)^{2} - 8 (3) - 21

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 27 + 2 \cdot 9 - 8 (3) - 21

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= 27 + 18 - 8 (3) - 21

Multiply and divide (left to right)

8 (3) : 24

8 (3)

Apply rule:

(a) = a

(3) = 3

= 8 \cdot 3

Multiply the numbers:

8 \cdot 3 = 24

= 24

= 27 + 18 - 24 - 21

Add and subtract (left to right)

27 + 18 - 24 - 21 : 0

27 + 18 - 24 - 21

27 + 18 = 45

= 45 - 24 - 21

45 - 24 = 21

= 21 - 21

21 - 21 = 0

= 0

= 0

- \frac{1}{3} (9)^{2} + 6 (9) + 1

16 \div 4 \times (3 - 1)

(- 36 + 18) + (- 42)

3 \times (3 + 4)

5^{3} \times 7^{2}