What is 3^2-4\times 1\times (-18) ?

The solution to 3^2-4\times 1\times (-18) is 81

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3^2-4\times 1\times (-18)

3^{2} - 4 \cdot 1 \cdot (- 18)

81

Solution steps

3^{2} - 4 \cdot 1 \cdot (- 18)

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 4 \cdot 1 \cdot (- 18)

Multiply and divide (left to right)

4 \cdot 1 \cdot (- 18) : - 72

4 \cdot 1 \cdot (- 18)

4 \cdot 1 = 4

= 4 (- 18)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 18) = - 4 \cdot 18 = - 72

= - 72

= 9 - (- 72)

Add and subtract (left to right)

9 - (- 72) : 81

9 - (- 72)

Apply rule

- (- a) = + a

- (- 72) = + 72

= 9 + 72

9 + 72 = 81

= 81

= 81

3 (- 1)^{2} - 2 (- 1) - 3

[(- 60) \div (- 10)] \div 3 + 2 (5 - 9)

- 15 - 4 + 18 - 10 - 11 + 8

4 (1)^{3} - 2 (1)

2 (1 0^{2} + 1) - 3 (1 0^{2} + 5) + 4 (1 0^{2} - 1)

What is 3^2-4\times 1\times (-18) ?
The solution to 3^2-4\times 1\times (-18) is 81