What is 3(-3)^2+2(-3)-8 ?

The solution to 3(-3)^2+2(-3)-8 is 13

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3(-3)^2+2(-3)-8

3 (- 3)^{2} + 2 (- 3) - 8

13

Solution steps

3 (- 3)^{2} + 2 (- 3) - 8

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 3 \cdot 9 + 2 (- 3) - 8

Multiply and divide (left to right)

3 \cdot 9 : 27

3 \cdot 9

3 \cdot 9 = 27

= 27

= 27 + 2 (- 3) - 8

Multiply and divide (left to right)

2 (- 3) : - 6

2 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 3) = - 2 \cdot 3 = - 6

= - 6

= 27 - 6 - 8

Add and subtract (left to right)

27 - 6 - 8 : 13

27 - 6 - 8

27 - 6 = 21

= 21 - 8

21 - 8 = 13

= 13

= 13

2 (4 + 3 - 2) + (- 5) + 3 (7 - 2)

- \frac{1}{2} (1) - 2

- 2^{3} - 4 (- 2)

(3 \frac{2}{5} + 1 \frac{7}{8}) + 2 \frac{1}{5}

1 - 5 (- 56)