What is 3(4)^2-3(4)-18 ?

The solution to 3(4)^2-3(4)-18 is 18

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3(4)^2-3(4)-18

3 (4)^{2} - 3 (4) - 18

18

Solution steps

3 (4)^{2} - 3 (4) - 18

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 3 \cdot 16 - 3 (4) - 18

Multiply and divide (left to right)

3 \cdot 16 : 48

3 \cdot 16

3 \cdot 16 = 48

= 48

= 48 - 3 (4) - 18

Multiply and divide (left to right)

3 (4) : 12

3 (4)

Apply rule:

(a) = a

(4) = 4

= 3 \cdot 4

Multiply the numbers:

3 \cdot 4 = 12

= 12

= 48 - 12 - 18

Add and subtract (left to right)

48 - 12 - 18 : 18

48 - 12 - 18

48 - 12 = 36

= 36 - 18

36 - 18 = 18

= 18

= 18

(+ 7) - (- 14) + (- 7) - (+ 4) - (+ 4)

(6 - 4 + 3) \times 9

308803 - 75152 \div 176 + 79008 + 0 \cdot 35402

10 \times 7 + 4 \times 3^{2} + 9

3^{4} \div 9 - 21