What is 4(-1)^2+5(-1)+3 ?

The solution to 4(-1)^2+5(-1)+3 is 2

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4(-1)^2+5(-1)+3

4 (- 1)^{2} + 5 (- 1) + 3

2

Solution steps

4 (- 1)^{2} + 5 (- 1) + 3

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 4 \cdot 1 + 5 (- 1) + 3

Multiply and divide (left to right)

4 \cdot 1 : 4

4 \cdot 1

4 \cdot 1 = 4

= 4

= 4 + 5 (- 1) + 3

Multiply and divide (left to right)

5 (- 1) : - 5

5 (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 1) = - 5 \cdot 1 = - 5

= - 5

= 4 - 5 + 3

Add and subtract (left to right)

4 - 5 + 3 : 2

4 - 5 + 3

4 - 5 = - 1

= - 1 + 3

- 1 + 3 = 2

= 2

= 2

2 \times 1 + 4

2 \times 1 + 3

2 \times 1 - 5

3 \times 2^{4} + 1

1 + 9 (4)^{4}