What is (3)^2-5(3)+7 ?

The solution to (3)^2-5(3)+7 is 1

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(3)^2-5(3)+7

(3)^{2} - 5 (3) + 7

1

Solution steps

(3)^{2} - 5 (3) + 7

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 9 - 5 (3) + 7

Multiply and divide (left to right)

5 (3) : 15

5 (3)

Apply rule:

(a) = a

(3) = 3

= 5 \cdot 3

Multiply the numbers:

5 \cdot 3 = 15

= 15

= 9 - 15 + 7

Add and subtract (left to right)

9 - 15 + 7 : 1

9 - 15 + 7

9 - 15 = - 6

= - 6 + 7

- 6 + 7 = 1

= 1

= 1

\frac{- 6 - 2 ( - 1 )}{4}

((- 5) - 2)^{2}

- 2 \cdot 0^{2}

2 \div 8 \div 3

(4 \times 6) \div 3