What is (-2)^2+4(-2)+3 ?

The solution to (-2)^2+4(-2)+3 is -1

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(-2)^2+4(-2)+3

(- 2)^{2} + 4 (- 2) + 3

- 1

Solution steps

(- 2)^{2} + 4 (- 2) + 3

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 + 4 (- 2) + 3

Multiply and divide (left to right)

4 (- 2) : - 8

4 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 2) = - 4 \cdot 2 = - 8

= - 8

= 4 - 8 + 3

Add and subtract (left to right)

4 - 8 + 3 : - 1

4 - 8 + 3

4 - 8 = - 4

= - 4 + 3

- 4 + 3 = - 1

= - 1

= - 1

2 + 2 \times 2

- 2 (1) + 3

1 \cdot (- 1) + 1

7 - (- 3) + (- 8) \div (- 8) - 3 - 3 - (- 1)

2^{2} - 5