The solution to 1/16+4-9 is -79/16

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1/16+4-9

Solution

\frac{1}{16} + 4 - 9

- \frac{79}{16}

Solution steps

\frac{1}{16} + 4 - 9

Follow the PEMDAS order of operations

Add and subtract (left to right)

\frac{1}{16} + 4 = \frac{65}{16}

\frac{1}{16} + 4

Convert element to fraction:

4 = \frac{4 \cdot 16}{16}

= \frac{4 \cdot 16}{16} + \frac{1}{16}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 16 + 1}{16}

4 \cdot 16 + 1 = 65

4 \cdot 16 + 1

Multiply the numbers:

4 \cdot 16 = 64

= 64 + 1

Add the numbers:

64 + 1 = 65

= 65

= \frac{65}{16}

= \frac{65}{16} - 9

\frac{65}{16} - 9 = - \frac{79}{16}

\frac{65}{16} - 9

Convert element to fraction:

9 = \frac{9 \cdot 16}{16}

= - \frac{9 \cdot 16}{16} + \frac{65}{16}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 9 \cdot 16 + 65}{16}

- 9 \cdot 16 + 65 = - 79

- 9 \cdot 16 + 65

Multiply the numbers:

9 \cdot 16 = 144

= - 144 + 65

Add/Subtract the numbers:

- 144 + 65 = - 79

= - 79

= \frac{- 79}{16}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{79}{16}

= - \frac{79}{16}

15 \div (2 + 3) + (2 - 5 \times 3)

12 \times 3 + 25 - 8 \times 4 - 17 + (47 - 32)

6^{3} - 108 \cdot 6 + 216

2 \cdot 5 + 2 \cdot 7 - 2 \cdot 4

40 - 13 \div 2