What is (4-1/4)\times (5-1/5) ?

The solution to (4-1/4)\times (5-1/5) is 18

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(4-1/4)\times (5-1/5)

(4 - \frac{1}{4}) \cdot (5 - \frac{1}{5})

18

Solution steps

(4 - \frac{1}{4}) (5 - \frac{1}{5})

Follow the PEMDAS order of operations

Calculate within parentheses

(4 - \frac{1}{4}) : \frac{15}{4}

4 - \frac{1}{4}

4 - \frac{1}{4} = \frac{15}{4}

4 - \frac{1}{4}

Convert element to fraction:

4 = \frac{4 \cdot 4}{4}

= \frac{4 \cdot 4}{4} - \frac{1}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{4 \cdot 4 - 1}{4}

4 \cdot 4 - 1 = 15

4 \cdot 4 - 1

Multiply the numbers:

4 \cdot 4 = 16

= 16 - 1

Subtract the numbers:

16 - 1 = 15

= 15

= \frac{15}{4}

= \frac{15}{4}

= \frac{15}{4} (5 - \frac{1}{5})

Calculate within parentheses

(5 - \frac{1}{5}) : \frac{24}{5}

5 - \frac{1}{5}

5 - \frac{1}{5} = \frac{24}{5}

5 - \frac{1}{5}

Convert element to fraction:

5 = \frac{5 \cdot 5}{5}

= \frac{5 \cdot 5}{5} - \frac{1}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 \cdot 5 - 1}{5}

5 \cdot 5 - 1 = 24

5 \cdot 5 - 1

Multiply the numbers:

5 \cdot 5 = 25

= 25 - 1

Subtract the numbers:

25 - 1 = 24

= 24

= \frac{24}{5}

= \frac{24}{5}

= \frac{15}{4} \cdot \frac{24}{5}

Multiply and divide (left to right)

\frac{15}{4} \cdot \frac{24}{5} : 18

\frac{15}{4} \cdot \frac{24}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{15 \cdot 24}{4 \cdot 5}

Cancel

\frac{15 \cdot 24}{4 \cdot 5} : 18

\frac{15 \cdot 24}{4 \cdot 5}

Factor the number:

15 = 5 \cdot 3

= \frac{5 \cdot 3 \cdot 24}{4 \cdot 5}

Cancel the common factor:

5

= \frac{3 \cdot 24}{4}

Divide the numbers:

\frac{24}{4} = 6

= 3 \cdot 6

Multiply the numbers:

3 \cdot 6 = 18

= 18

= 18

= 18

1 0^{2} + 2 5^{2}

(3 - 2 + 1) \times (1 + 1 - 1)

1 - 2 - 9 - 20 - 108 + 4

- 2 + 5 - (- 1)

3^{3} - 8 + 0