What is (-12)^2-4\times 4\times 9 ?

The solution to (-12)^2-4\times 4\times 9 is 0

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(-12)^2-4\times 4\times 9

(- 12)^{2} - 4 \cdot 4 \cdot 9

0

Solution steps

(- 12)^{2} - 4 \cdot 4 \cdot 9

Follow the PEMDAS order of operations

Calculate exponents

(- 12)^{2} : 144

(- 12)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 12)^{2} = 1 2^{2} = 144

= 144

= 144 - 4 \cdot 4 \cdot 9

Multiply and divide (left to right)

4 \cdot 4 \cdot 9 : 144

4 \cdot 4 \cdot 9

4 \cdot 4 = 16

= 16 \cdot 9

16 \cdot 9 = 144

= 144

= 144 - 144

Add and subtract (left to right)

144 - 144 : 0

144 - 144

144 - 144 = 0

= 0

= 0

\frac{1}{2} - 8 (\frac{1}{4} + 1)

(1 + 2)^{2} + 14 \div 2 + 5

1^{2} + 2 (1) - 1

(\frac{7}{2} \div \frac{4}{4}) - \frac{3}{8}

\frac{2}{9} \times \frac{3}{4} \times (- 7)

What is (-12)^2-4\times 4\times 9 ?
The solution to (-12)^2-4\times 4\times 9 is 0