What is 1/2 \times (-1)-1 ?

The solution to 1/2 \times (-1)-1 is -3/2

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1/2 \times (-1)-1

\frac{1}{2} \cdot (- 1) - 1

- \frac{3}{2}

Solution steps

\frac{1}{2} (- 1) - 1

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{1}{2} (- 1) : - \frac{1}{2}

\frac{1}{2} (- 1)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{1}{2} (- 1) = - \frac{1}{2} \cdot 1 = - \frac{1}{2}

= - \frac{1}{2}

= - \frac{1}{2} - 1

Add and subtract (left to right)

- \frac{1}{2} - 1 : - \frac{3}{2}

- \frac{1}{2} - 1

- \frac{1}{2} - 1 = - \frac{3}{2}

- \frac{1}{2} - 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} - \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 - 1}{2}

- 1 \cdot 2 - 1 = - 3

- 1 \cdot 2 - 1

Multiply the numbers:

1 \cdot 2 = 2

= - 2 - 1

Subtract the numbers:

- 2 - 1 = - 3

= - 3

= \frac{- 3}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{2}

= - \frac{3}{2}

= - \frac{3}{2}

15 - [- 5 - (7 - 5)] - 20

- 2 (- 1)^{2} + 5

7^{2} - 8^{2} + 7

(3 - 2^{2}) + 5

(2 + 6)^{2}