The solution to 4(-2)^2-5 is 11

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4(-2)^2-5

Solution

4 (- 2)^{2} - 5

11

Solution steps

4 (- 2)^{2} - 5

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= 4 \cdot 4 - 5

Multiply and divide (left to right)

4 \cdot 4 : 16

4 \cdot 4

4 \cdot 4 = 16

= 16

= 16 - 5

Add and subtract (left to right)

16 - 5 : 11

16 - 5

16 - 5 = 11

= 11

= 11

(5 - 2)^{2} + 8 \div 4

2 (- 1)^{2} + 3 (2)^{3} - 4 (\frac{3}{4})

20 \frac{\frac{( - 4 )}{- 6}}{( 5 - 8 )} + 4 \times (1 - 2)

42 \div [(- 6) - (- 3)] + 28 \div [- 6 - (- 8)]

(6 - 8 + 5) - 4 + 3 + 1