What is 2(-1)^2+3(2)^3-4(3/4) ?

The solution to 2(-1)^2+3(2)^3-4(3/4) is 23

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2(-1)^2+3(2)^3-4(3/4)

2 (- 1)^{2} + 3 (2)^{3} - 4 (\frac{3}{4})

23

Solution steps

2 (- 1)^{2} + 3 (2)^{3} - 4 (\frac{3}{4})

Follow the PEMDAS order of operations

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 2 \cdot 1 + 3 (2)^{3} - 4 (\frac{3}{4})

Calculate exponents

(2)^{3} : 8

(2)^{3}

(2)^{3} = 8

= 8

= 2 \cdot 1 + 3 \cdot 8 - 4 (\frac{3}{4})

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2 + 3 \cdot 8 - 4 (\frac{3}{4})

Multiply and divide (left to right)

3 \cdot 8 : 24

3 \cdot 8

3 \cdot 8 = 24

= 24

= 2 + 24 - 4 (\frac{3}{4})

Multiply and divide (left to right)

4 (\frac{3}{4}) : 3

4 (\frac{3}{4})

Apply rule:

(a) = a

(\frac{3}{4}) = \frac{3}{4}

= 4 \cdot \frac{3}{4}

Convert element to fraction:

4 = \frac{4}{1}

= \frac{4}{1} \cdot \frac{3}{4}

Cross-cancel common factor:

4

= \frac{3}{1}

Divide the numbers:

\frac{3}{1} = 3

= 3

= 2 + 24 - 3

Add and subtract (left to right)

2 + 24 - 3 : 23

2 + 24 - 3

2 + 24 = 26

= 26 - 3

26 - 3 = 23

= 23

= 23

20 \frac{\frac{( - 4 )}{- 6}}{( 5 - 8 )} + 4 \times (1 - 2)

42 \div [(- 6) - (- 3)] + 28 \div [- 6 - (- 8)]

(6 - 8 + 5) - 4 + 3 + 1

7 (- 2) - (- 2) (- 8)

6^{0} + 7^{2}